In a deadheaded pump, what happens to the energy transferred to the fluid if the fluid is not leaving the casing?

In a deadheaded pump, what happens to the energy transferred to the fluid if the fluid is not leaving the casing?

• A. Energy Is Converted To Heat, Raising Fluid Temperature
• B. Energy Increases The Fluid Velocity
• C. Energy Is Converted To Potential Energy
• D. Energy Is Stored In The Impeller

Answer: (A)

When a pump is deadheaded, the discharge is blocked so the fluid cannot leave the casing. The pump still does work on the fluid, which tends to raise pressure, but with essentially no flow there is nowhere for that energy to go as velocity or to be stored as lifted potential energy. The majority of the input energy is dissipated by viscous friction and turbulence inside the fluid and around the impeller and casing, turning that mechanical energy into heat. That heat raises the fluid’s temperature slightly. So, even though the fluid isn’t being moved downstream, the energy ends up as heat rather than increasing velocity or storing as potential energy.

When a pump is deadheaded, the discharge is blocked so the fluid cannot leave the casing. The pump still does work on the fluid, which tends to raise pressure, but with essentially no flow there is nowhere for that energy to go as velocity or to be stored as lifted potential energy. The majority of the input energy is dissipated by viscous friction and turbulence inside the fluid and around the impeller and casing, turning that mechanical energy into heat. That heat raises the fluid’s temperature slightly. So, even though the fluid isn’t being moved downstream, the energy ends up as heat rather than increasing velocity or storing as potential energy.